The product of the second and third of three consecutive integers is 2 more than 13 times the first integer. Suppose that f(x) has a domain of [5,12] and a range of [4,13].
With this system we aren’t going to be able to completely avoid fractions.
However, it looks like if we solve the second equation for \(x\) we can minimize them. \[\begin3x & = 6y 2\ x & = 2y \frac\end\] Now, substitute this into the first equation and solve the resulting equation for \(y\).
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