# Variable Assignment

And this shows that that exception is not valid, PHP assignment for objects still makes a copy of variable and does not creates a real reference, albeit changing an object variable members will cause both copies to change.

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For the assignment to work successfully, the type of the variable on the left hand side should be the same as the type returned by the expression.

The statement in line 10 of the simple adder program is an example of an assignment statement involving an arithmetic expression. As discussed above, variables can be thought of as named boxes into which values can be stored. a variable) appears in an expression, it represents the value currently stored in that box.

Although addition, subtraction and multiplication are the same for both integers and reals (floating point numbers), division is different.

If you write (see later for declaration and initialisation of variables on the same line): The order of execution of mathematical operations is governed by rules of precedence.

These are similar to those of algebraic expressions.

Parentheses are always evaluated first, followed by multiplication, division and modulus operations. The best thing, however, is to use parentheses (brackets) instead of trying to remember the rules.except that the expression’s value is not printed and is not put in the value history (see Value History). If the beginning of the argument string of the (gdb) whatis g type = double (gdb) p g

Parentheses are always evaluated first, followed by multiplication, division and modulus operations. The best thing, however, is to use parentheses (brackets) instead of trying to remember the rules.

except that the expression’s value is not printed and is not put in the value history (see Value History). If the beginning of the argument string of the (gdb) whatis g type = double (gdb) p g \$1 = 1 (gdb) set g=4 (gdb) p g \$2 = 1 (gdb) r The program being debugged has been started already. (y or n) y Starting program: /home/smith/cc_progs/"/home/smith/cc_progs/a.out": can't open to read symbols: Invalid bfd target. allows more implicit conversions in assignments than C; you can freely store an integer value into a pointer variable or vice versa, and you can convert any structure to any other structure that is the same length or shorter.

that every variable in a program is given a value explicitly before any attempt is made to use it.

PHP uses a temporary variable for combined assign-operators (unlike Java Script), therefore the left-hand-side (target) gets evaluated last.

Input:\$a = \$b \$c; Meaning:\$a = (\$b \$c) \$a; Not:\$a = \$a (\$b \$c); This can be important if the target gets modified inside the expression.\$a = 0;\$a = ( \$a) ( \$a); // yields 5 (instead of 4) Document says:"An exception to the usual assignment by value behaviour within PHP occurs with objects, which are assigned by reference in PHP 5.

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Parentheses are always evaluated first, followed by multiplication, division and modulus operations. The best thing, however, is to use parentheses (brackets) instead of trying to remember the rules.except that the expression’s value is not printed and is not put in the value history (see Value History). If the beginning of the argument string of the (gdb) whatis g type = double (gdb) p g \$1 = 1 (gdb) set g=4 (gdb) p g \$2 = 1 (gdb) r The program being debugged has been started already. (y or n) y Starting program: /home/smith/cc_progs/"/home/smith/cc_progs/a.out": can't open to read symbols: Invalid bfd target. allows more implicit conversions in assignments than C; you can freely store an integer value into a pointer variable or vice versa, and you can convert any structure to any other structure that is the same length or shorter.that every variable in a program is given a value explicitly before any attempt is made to use it.PHP uses a temporary variable for combined assign-operators (unlike Java Script), therefore the left-hand-side (target) gets evaluated last.Input:\$a = \$b \$c; Meaning:\$a = (\$b \$c) \$a; Not:\$a = \$a (\$b \$c); This can be important if the target gets modified inside the expression.\$a = 0;\$a = ( \$a) ( \$a); // yields 5 (instead of 4) Document says:"An exception to the usual assignment by value behaviour within PHP occurs with objects, which are assigned by reference in PHP 5.The values of constants must always be assigned when they are created.The use of constants helps programmers avoid inadvertent alterations of information that should never be changed. Your first inclination might be to think of this as "equal to". It really means that the left operand gets set to the value of the expression on the right (that is, "gets set to").The value of an assignment expression is the value assigned.Like variables, symbolic constants have types and names.A constant is declared and initialised in a similar way to variables but with a specific instruction to the compiler that the value cannot be changed by the program.

= 1 (gdb) set g=4 (gdb) p g = 1 (gdb) r The program being debugged has been started already. (y or n) y Starting program: /home/smith/cc_progs/"/home/smith/cc_progs/a.out": can't open to read symbols: Invalid bfd target. allows more implicit conversions in assignments than C; you can freely store an integer value into a pointer variable or vice versa, and you can convert any structure to any other structure that is the same length or shorter.that every variable in a program is given a value explicitly before any attempt is made to use it.PHP uses a temporary variable for combined assign-operators (unlike Java Script), therefore the left-hand-side (target) gets evaluated last.Input:\$a = \$b \$c; Meaning:\$a = (\$b \$c) \$a; Not:\$a = \$a (\$b \$c); This can be important if the target gets modified inside the expression.\$a = 0;\$a = ( \$a) ( \$a); // yields 5 (instead of 4) Document says:"An exception to the usual assignment by value behaviour within PHP occurs with objects, which are assigned by reference in PHP 5.The values of constants must always be assigned when they are created.The use of constants helps programmers avoid inadvertent alterations of information that should never be changed. Your first inclination might be to think of this as "equal to". It really means that the left operand gets set to the value of the expression on the right (that is, "gets set to").The value of an assignment expression is the value assigned.Like variables, symbolic constants have types and names.A constant is declared and initialised in a similar way to variables but with a specific instruction to the compiler that the value cannot be changed by the program.

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